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# numpy.logical_xor

`numpy.``logical_xor`(x1, x2[, out])

  Compute the truth value of x1 XOR x2 elementwise.

  Parameters: | x1, x2 : array_like Logical XOR is applied to the elements of x1 and x2. They have to be of the same shape.
  Returns: | y : {ndarray, bool} Boolean result with the same shape as x1 and x2 of the logical XOR operation on elements of x1 and x2.

  See also

  `logical_and`, `logical_or`, `logical_not`, `bitwise_xor`

  Examples

      >>> np.logical_xor(True, False)
      True
      >>> np.logical_xor([True, True, False, False], [True, False, True, False])
      array([False,  True,  True, False], dtype=bool)

      >>> x = np.arange(5)
      >>> np.logical_xor(x < 1, x > 3)
      array([ True, False, False, False,  True], dtype=bool)

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