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# numpy.core.defchararray.count

`numpy.core.defchararray.``count`(a, sub, start=0, end=None)

  Returns an array with the number of non-overlapping occurrences of substring sub in the range [start, end].

  Calls str.count element-wise.

  Parameters : | a : array_like of str or unicode sub : str or unicode The substring to search for. start, end : int, optional Optional arguments start and end are interpreted as slice notation to specify the range in which to count.
  Returns : | out : ndarray Output array of ints.

  See also

  `str.count`

  Examples

      >>> c = np.array(['aAaAaA', '  aA  ', 'abBABba'])
      >>> c
      array(['aAaAaA', '  aA  ', 'abBABba'],
          dtype='|S7')
      >>> np.char.count(c, 'A')
      array([3, 1, 1])
      >>> np.char.count(c, 'aA')
      array([3, 1, 0])
      >>> np.char.count(c, 'A', start=1, end=4)
      array([2, 1, 1])
      >>> np.char.count(c, 'A', start=1, end=3)
      array([1, 0, 0])

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