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# numpy.any

`numpy.``any`(a, axis=None, out=None)

  Test whether any array element along a given axis evaluates to True.

  Returns single boolean unless axis is not `None`

  Parameters : | a : array_like Input array or object that can be converted to an array. axis : int, optional Axis along which a logical OR is performed. The default (axis = None) is to perform a logical OR over a flattened input array. axis may be negative, in which case it counts from the last to the first axis. out : ndarray, optional Alternate output array in which to place the result. It must have the same shape as the expected output and its type is preserved (e.g., if it is of type float, then it will remain so, returning 1.0 for True and 0.0 for False, regardless of the type of a). See doc.ufuncs (Section “Output arguments”) for details.
  Returns : | any : bool or ndarray A new boolean or ndarray is returned unless out is specified, in which case a reference to out is returned.

  See also

  `ndarray.any`
    equivalent method
  `all`
    Test whether all elements along a given axis evaluate to True.

  Notes

  Not a Number (NaN), positive infinity and negative infinity evaluate to True because these are not equal to zero.

  Examples

      >>> np.any([[True, False], [True, True]])
      True

      >>> np.any([[True, False], [False, False]], axis=0)
      array([ True, False], dtype=bool)

      >>> np.any([-1, 0, 5])
      True

      >>> np.any(np.nan)
      True

      >>> o=np.array([False])
      >>> z=np.any([-1, 4, 5], out=o)
      >>> z, o
      (array([ True], dtype=bool), array([ True], dtype=bool))
      >>> # Check now that z is a reference to o
      >>> z is o
      True
      >>> id(z), id(o) # identity of z and o
      (191614240, 191614240)

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