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# numpy.ufunc.outer

`ufunc.``outer`(A, B)

  Apply the ufunc op to all pairs (a, b) with a in A and b in B.

  Let `M = A.ndim`, `N = B.ndim`. Then the result, C, of `op.outer(A, B)` is an array of dimension M + N such that:

  For A and B one-dimensional, this is equivalent to:

      r = empty(len(A),len(B))
      for i in xrange(len(A)):
          for j in xrange(len(B)):
              r[i,j] = op(A[i], B[j]) # op = ufunc in question

  Parameters : | A : array_like First array B : array_like Second array
  Returns : | r : ndarray Output array

  See also

  `numpy.outer`

  Examples

      >>> np.multiply.outer([1, 2, 3], [4, 5, 6])
      array([[ 4,  5,  6],
             [ 8, 10, 12],
             [12, 15, 18]])

  A multi-dimensional example:

      >>> A = np.array([[1, 2, 3], [4, 5, 6]])
      >>> A.shape
      (2, 3)
      >>> B = np.array([[1, 2, 3, 4]])
      >>> B.shape
      (1, 4)
      >>> C = np.multiply.outer(A, B)
      >>> C.shape; C
      (2, 3, 1, 4)
      array([[[[ 1,  2,  3,  4]],
              [[ 2,  4,  6,  8]],
              [[ 3,  6,  9, 12]]],
             [[[ 4,  8, 12, 16]],
              [[ 5, 10, 15, 20]],
              [[ 6, 12, 18, 24]]]])

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