# numpy.ma.choose

ma.choose(indices, choices, out=None, mode='raise')

  Use an index array to construct a new array from a list of choices.

  Given an array of integers and a list of n choice arrays, this method will create a new array that merges each of the choice arrays. Where a value in index is i, the new array will have the value that choices[i] contains in the same place.

  Parameters
    indices ndarray of ints

      This array must contain integers in `[0, n-1]`, where n is the number of choices.

    choices sequence of arrays

      Choice arrays. The index array and all of the choices should be broadcastable to the same shape.

    out array, optional

      If provided, the result will be inserted into this array. It should be of the appropriate shape and `dtype`.

    mode{‘raise’, ‘wrap’, ‘clip’}, optional

      Specifies how out-of-bounds indices will behave.

      - ‘raise’ : raise an error

      - ‘wrap’ : wrap around

      - ‘clip’ : clip to the range

  Returns
    merged_array array

  See also

  `choose`

    equivalent function

  Examples

      >>> choice = np.array([[1,1,1], [2,2,2], [3,3,3]])
      >>> a = np.array([2, 1, 0])
      >>> np.ma.choose(a, choice)
      masked_array(data=[3, 2, 1],
                   mask=False,
             fill_value=999999)

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