# numpy.fromregex

numpy.fromregex(file, regexp, dtype, encoding=None)

  Construct an array from a text file, using regular expression parsing.

  The returned array is always a structured array, and is constructed from all matches of the regular expression in the file. Groups in the regular expression are converted to fields of the structured array.

  Parameters
    file path or file

      Filename or file object to read.

      Changed in version 1.22.0: Now accepts `os.PathLike` implementations.

    regexp str or regexp

      Regular expression used to parse the file. Groups in the regular expression correspond to fields in the dtype.

    dtype dtype or list of dtypes

      Dtype for the structured array; must be a structured datatype.

    encoding str, optional

      Encoding used to decode the inputfile. Does not apply to input streams.

      New in version 1.14.0.

  Returns
    output ndarray

      The output array, containing the part of the content of file that was matched by regexp. output is always a structured array.

  Raises
    TypeError

      When `dtype` is not a valid dtype for a structured array.

  See also

  `fromstring`, `loadtxt`

  Notes

  Dtypes for structured arrays can be specified in several forms, but all forms specify at least the data type and field name. For details see basics.rec.

  Examples

      >>> from io import StringIO
      >>> text = StringIO("1312 foo\n1534  bar\n444   qux")

      >>> regexp = r"(\d+)\s+(...)"  # match [digits, whitespace, anything]
      >>> output = np.fromregex(text, regexp,
      ...                       [('num', np.int64), ('key', 'S3')])
      >>> output
      array([(1312, b'foo'), (1534, b'bar'), ( 444, b'qux')],
            dtype=[('num', '<i8'), ('key', 'S3')])
      >>> output['num']
      array([1312, 1534,  444])

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