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# scipy.stats.chi2_contingency

`scipy.stats.``chi2_contingency`(observed, correction=True)

  Chi-square test of independence of variables in a contingency table.

  This function computes the chi-square statistic and p-value for the hypothesis test of independence of the observed frequencies in the contingency table [R170] observed. The expected frequencies are computed based on the marginal sums under the assumption of independence; see scipy.stats.expected_freq. The number of degrees of freedom is (expressed using numpy functions and attributes):

      dof = observed.size - sum(observed.shape) + observed.ndim - 1

  Parameters : | observed : array_like The contingency table. The table contains the observed frequencies (i.e. number of occurrences) in each category. In the two-dimensional case, the table is often described as an “R x C table”. correction : bool, optional If True, and the degrees of freedom is 1, apply Yates’ correction for continuity.
  Returns : | chi2 : float The chi-square test statistic. Without the Yates’ correction, this is the sum of the squares of the observed values minus the expected values, divided by the expected values. With Yates’ correction, 0.5 is subtracted from the squared differences before dividing by the expected values. p : float The p-value of the test dof : int Degrees of freedom expected : ndarray, same shape as observed The expected frequencies, based on the marginal sums of the table.

  See also

  `contingency.expected_freq`, `fisher_exact`, `chisquare`

  Notes

  An often quoted guideline for the validity of this calculation is that the test should be used only if the observed and expected frequency in each cell is at least 5.

  This is a test for the independence of different categories of a population. The test is only meaningful when the dimension of observed is two or more. Applying the test to a one-dimensional table will always result in expected equal to observed and a chi-square statistic equal to 0.

  This function does not handle masked arrays, because the calculation does not make sense with missing values.

  Like stats.chisquare, this function computes a chi-square statistic; the convenience this function provides is to figure out the expected frequencies and degrees of freedom from the given contingency table. If these were already known, and if the Yates’ correction was not required, one could use stats.chisquare. That is, if one calls:

      chi2, p, dof, ex = chi2_contingency(obs, correction=False)

  then the following is true:

      (chi2, p) == stats.chisquare(obs.ravel(), f_exp=ex.ravel(),
                                   ddof=obs.size - 1 - dof)

  References

  [R170] | (1, 2) http://en.wikipedia.org/wiki/Contingency_table

  Examples

  A two-way example (2 x 3):

      >>> obs = np.array([[10, 10, 20], [20, 20, 20]])
      >>> chi2_contingency(obs)
      (2.7777777777777777,
       0.24935220877729619,
       2,
       array([[ 12.,  12.,  16.],
              [ 18.,  18.,  24.]]))

  A four-way example (2 x 2 x 2 x 2):

      >>> obs = np.array(
      ...     [[[[12, 17],
      ...        [11, 16]],
      ...       [[11, 12],
      ...        [15, 16]]],
      ...      [[[23, 15],
      ...        [30, 22]],
      ...       [[14, 17],
      ...        [15, 16]]]])
      >>> chi2_contingency(obs)
      (8.7584514426741897,
       0.64417725029295503,
       11,
       array([[[[ 14.15462386,  14.15462386],
                [ 16.49423111,  16.49423111]],
               [[ 11.2461395 ,  11.2461395 ],
                [ 13.10500554,  13.10500554]]],
              [[[ 19.5591166 ,  19.5591166 ],
                [ 22.79202844,  22.79202844]],
               [[ 15.54012004,  15.54012004],
                [ 18.10873492,  18.10873492]]]]))

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