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# scipy.sparse.dok_matrix.update

`dok_matrix.``update`([E], **F) → None. Update D from dict/iterable E and F.

  If E present and has a .keys() method, does: for k in E: D[k] = E[k] If E present and lacks .keys() method, does: for (k, v) in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]

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- SciPy v0.12 Reference Guide (DRAFT) »
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