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# scipy.misc.comb

`scipy.misc.``comb`(N, k, exact=0)

  The number of combinations of N things taken k at a time.

  This is often expressed as “N choose k”.

  Parameters : | N : int, ndarray Number of things. k : int, ndarray Number of elements taken. exact : int, optional If exact is 0, then floating point precision is used, otherwise exact long integer is computed.
  Returns : | val : int, ndarray The total number of combinations.

  Notes

  - Array arguments accepted only for exact=0 case.
  - If k > N, N < 0, or k < 0, then a 0 is returned.

  Examples

      >>> k = np.array([3, 4])
      >>> n = np.array([10, 10])
      >>> sc.comb(n, k, exact=False)
      array([ 120.,  210.])
      >>> sc.comb(10, 3, exact=True)
      120L

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